On 03/05/2007, at 5:43 AM, Lutz, Charles D wrote: > I’m looking at the example for “Call” (Section 3.7.3 of “A Tutorial > Introduction”, > > v 21 Apr 2007) and I’m missing the point about how this defines > disjunction: > > X ; Y :- call(X). > X ; Y :- call(Y). <gripe> I've got to say, this is one of the things that really annoys me about Prolog. Rather than define ';' explicitly as part of the language, it tries to be clever and express its definition _in_ the language, as just another operator. Theoretically that's very neat, but practically it's a real pain. It's because of this that you get mysterious error messages such as "*** trying to redefine a built-in predicate: (;) / 2" when a straightforward "syntax error" would be more appropriate. Maybe in 0.001% of cases you might want to do something tricky, treating ';' as an operator, but the rest of the time it just causes trouble. </gripe> Malcolm -- Many clever men like you have trusted to civilisation. Many clever Babylonians, many clever Egyptians, Many clever men at the end of Rome. - G.K.Chesterton, The Napoleon of Notting HillReceived on Thu May 03 2007 - 01:55:43 CEST
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