Caroline Nabil wrote: > Ok,thanks a lot for your help .I tried it with member predicate example > and it is working but i have another problem with that i have a lot of > solutions and the program takes a lot of time running so i want to know > if there is a way to stop it after a few seconds or a few set of > solutions..and i tried timeout/3 but the problem with it ,it doesnt give > me the output in the list as it should be, to explain more what i mean > here is my predicate : > > %Objects is a list of structs which i send to solve and i am expecting > to get the result in List > > solveAll(Objects,List):- > timeout(findall(Objects,solve(Objects),List),5,writeln(done)). Here is a working example: :- lib(timeout). p(L) :- findall(X, timeout(between(1,1000000000,1,X), 1, fail), L). -- JoachimReceived on Mon Apr 26 2010 - 11:41:51 CEST
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