Re: [eclipse-clp-users] How to expand domain of a variable

The right hand side of ::/2 is also just a list, only in a slightly
different format from what you have as input.

So you just translate your input list [[10, 20], [15, 30], [40, 50]]
to the kind of list that the ::/2 predicate expects, i.e.

input_to_intervals(In, Out) :-
	( foreach([Min,Max],In), foreach(Min..Max,Out) do true ).


?- input_to_intervals([[10, 20], [15, 30], [40, 50]], Intervals),
    X :: Intervals.

Intervals = [10 .. 20, 15 .. 30, 40 .. 50]
X = X{[10 .. 30, 40 .. 50]}
Yes (0.00s cpu)




Sergey Dymchenko wrote:
> Thank you, but the main question how to construct that domain X ::
> [10..20, 15..30, 40..50] if I have a list of interval boundaries [[10,
> 20], [15, 30], [40, 50]] (I read them from a file, number of intervals
> can be different).
> I can't see how do this simpler than in my model/2
> 
> Sergey.
> 
> On Sun, Nov 6, 2011 at 2:18 AM, Joachim Schimpf <jschimpf_at_...311...> wrote:
>> Sergey Dymchenko wrote:
>>> [eclipse 1]: model([[10, 20], [15, 30], [40, 50]], Domain),
>>> query(Domain, 1, A1), query(Domain, 10, A2), query(Domain, 35, A3).
>>>
>>> Domain = [10 .. 30, 40 .. 50]
>>> A1 = "No"
>>> A2 = "Yes"
>>> A3 = "No"
>>> Yes (0.00s cpu)
>> Hi Sergey,
>>
>> you can achieve that simply via
>>
>> ?- X :: [10..20, 15..30, 40..50], is_in_domain(1, X, B1), is_in_domain(10, X, B2).
>> X = X{[10 .. 30, 40 .. 50]}
>> B1 = no
>> B2 = yes
>> Yes (0.00s cpu)
>>
>>
>> -- Joachim