Hi Philipp, this program works as you expect: :-lib(fd). :-lib(propia). con1(1,1,0). con1(1,2,0). con1(1,3,0). cons(X,Y,B) :- con1(X,Y,B) infers most. execute(X) :- X#::[1,2,3], cons(1,X, B1), #=(X, 1, B2), B1 + B2 #>= 1. This program should be (in my opinion) equivalent to yours. Best regards -- [ Wit Jakuczun http://www.linkedin.com/in/jakuczunwit ] 2010/4/22 Philipp Marcus <marcus_at_...247...>: > Hi, > > given the following simple program: > > :-lib(fd). > :-lib(propia). > > con1(1,1,0). > con1(1,2,0). > con1(1,3,0). > > cons(X,Y,B) :- > con1(X,Y,B) infers most. > > execute(X) :- > X#::[1,2,3], cons(1,X) #\/ X#=1. > > I'd expect that the domain of X is reduced to the value 1 as the first term > cons(1,X) can never be true. But i only get the answer > > ?- execute(X). > No (0.00s cpu) > > I am wondering as (false \/ X=1 ) should imply that X has to be 1 to be > true. > > Thanks in advance and best regards, > Philipp > > > ------------------------------------------------------------------------------ > > _______________________________________________ > ECLiPSe-CLP-Users mailing list > ECLiPSe-CLP-Users_at_lists.sourceforge.net > https://lists.sourceforge.net/lists/listinfo/eclipse-clp-users > >Received on Thu Apr 22 2010 - 13:42:14 CEST
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