Hi folks, As a new user both of Prolog and of ECLiPSe, I'll probably have a lot of questions. I'm slllooooowwwwwllly working through the tutorial book. I'm finding I need more explanations for quite a lot of the examples. Currently I'm looking at section 4.6, "Matching". To play with the example, I made both a "normal" version and a "matching" version: %From section 4.6: %version without matching: p1(f(a, X)) :- writeln(X). %version with matching: p2(f(a, X)) ?- writeln(X). Here are some runs: [eclipse 17]: p2(F). No (0.00s cpu) [eclipse 18]: p2(f(A, B)). No (0.00s cpu) [eclipse 19]: p2(f(A, b)). No (0.00s cpu) [eclipse 20]: p2(f(a, b)). b Yes (0.00s cpu) [eclipse 21]: p1(F). X F = f(a, X) Yes (0.00s cpu) [eclipse 22]: p1(f(A, B)). B A = a B = B Yes (0.00s cpu) [eclipse 23]: p1(f(A, b)). b A = a Yes (0.00s cpu) [eclipse 24]: p1(f(a, b)). b Yes (0.00s cpu) To be honest, the outputs of both of these variants are not totally clear to me. First off, what does it "mean" to have "f(a, X)" inside of the head clause? Apart from saying p1 or p2 is a clause of arity 1, whose argument is another clause of arity 2, what is the "practical" meaning of it? This might help me to understand the first output of p1 and the difference between the second and third outputs of p1. In all success cases, I'm taking it that the first line of output is the result of the writeln/1. Thanks in advance for any tips, Chuck Lutz Lockheed Martin Systems of Systems Engineering BMC4I Modeling and Simulation Moorestown, NJ (856)638-7234 (office) charles.d.lutz_at_...53... "A graphic is never an end in itself; it is a moment in the process of decision making." - Jacques BertinReceived on Tue May 08 2007 - 16:48:19 CEST
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